Python Program to Check Vowel or Consonant
easyif / elsePython
A short program that shows how Python's in operator can replace a long chain of comparisons.
The question
Read one alphabet letter (it may be upper or lower case) and print Vowel or Consonant.
The code
program.py
ch = input().strip()
if ch.lower() in "aeiou":
print("Vowel")
else:
print("Consonant")Input
b
Output
Consonant
How it works
- 1Read one character; .strip() removes any accidental spaces.
- 2.lower() turns A into a, so capital letters are handled too.
- 3ch in "aeiou" is True when the letter is one of the five vowels.
Common mistakes
- Writing if ch == 'a' or 'e' or 'i' — this is always True in Python and every letter becomes a vowel.
- Forgetting upper case: without .lower(), E is reported as a consonant.
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